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2y^2-25y+72=0
a = 2; b = -25; c = +72;
Δ = b2-4ac
Δ = -252-4·2·72
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-7}{2*2}=\frac{18}{4} =4+1/2 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+7}{2*2}=\frac{32}{4} =8 $
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